Question

how much h2so4 of density 1.84 gm/ml (98% pure by weight) should be taken to make 1 l normal solution correct answer instant brailiest

Answer 1

Answer:

98% by weight of solution means 98g of H

2

SO

4

is present in 100g of solution.

Volume of solution =

density of solution

mass of solution

= (1.8×1000)g/L

100g

Volume of solution =

18  1  L  

Per cent H 2

SO  4

w/v of solution = molarity =  

volume of solution (in L)

number of moles of H 2

SO 4

Molarity =

volume of solution  

given mass of H  

2  

SO

4 / molar mass of H 2 SO 4

Molarity = 1/18

98/98 =18M

Explanation: