how much heat energy gained when 0.6kg of water at 25°c is brought to its boiling point?
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Answered by
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Answer:
q= mass = 5kg
m=mass=5kg
c=specific heat capacity= 4185.5 J/kg/K
T= temperature difference=T2-T1=100–20=80c=353K
q=mcT=5kg*4185.5 J/kg/K*353K=7387407.5 J
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