Question

How much heat energy in Joules is necessary to raise the temperature of 5 kg of water from

20°

to 100° ?

(1) 1672 KJ (2) 167200 J

(3) 16720 J (4) 1672 J​

Answer 1

Answer:

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of water

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °C

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °CAll you need to do is essentially multiply specific Heat Capacity with the two values above.

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °CAll you need to do is essentially multiply specific Heat Capacity with the two values above.The magnitude of Heat in Joules =

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °CAll you need to do is essentially multiply specific Heat Capacity with the two values above.The magnitude of Heat in Joules =(4.186 J / g °C) x (5,000 g) x (80 °C) = 1,674,400 Joules

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °CAll you need to do is essentially multiply specific Heat Capacity with the two values above.The magnitude of Heat in Joules =(4.186 J / g °C) x (5,000 g) x (80 °C) = 1,674,400 JoulesYou can convert this into Kilo Joules by dividing it with 1,000, and further into Mega Joules by dividing again with 1,000.

Answer 2

Answer: The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.Now, We have5 kg of water = 5,000 gram of waterTemperature Difference = 100 °C - 20 °C = 80 °CAll you need to do is essentially multiply specific Heat Capacity with the two values above.The magnitude of Heat in Joules =(4.186 J / g °C) x (5,000 g) x (80 °C) = 1,674,400 JoulesYou can convert this into Kilo Joules by dividing it with 1,000, and further into Mega Joules by dividing again with 1,000.

Hope this will help you friend!!!