Question

How much heat energy in joules is necessary to raise the temperature of 5 kg of water from 20 to 100 degree?

Answer 1

This uses specific heat capacity. The formula is E=mcθ where E is energy in joules, m is mass of substance in kg, c is the specific heat capacity of a substance in joules per kelvin per kg and θ is the change in temperature in either Celsius or Kelvin.

Specific heat capacity of water is 4200 (to 2 sig. Fig.)

m=5kg

C=4200

Change in temperature=100-20=80

E=5*4200*80

E=1680000J

Answer 2

Answer:

nice explanation by you sir