Question

How much heat energy in joules is required to convert 30g of watermark at 700C to 30g of water at 1000C ?​

Answer 1

Answer:

Let Q be the heat required to convert 200 g of water at `40^@C "into" 100^@C`, then

`Q= mcDeltaT = (200)(1.0)(100-40) = 12000 cal`

Now, suppose `m_0` mass of steam converts into water to liberate this much amount of heat, then

`m_0 = Q/L = 12000/539 = 22.26 g `

Since, it is less than 30g, the temperature of the mixture is `100^@C`.

Mass of steam in the mixture `= 30- 22.26 = 7.74g `

and mass of water in the mixture `= 200 + 22.26 = 222.26g `

Explanation:

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