How much heat energy. is necessary to raise the temperature of 5 kg of water from 20℃ to 100℃ ?
Answers
Answered by
4
Explanation:
C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules.
Answered by
4
Answer:
Quantity of heat required to raise 5 kg of water from 20 0C to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.) For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.
Explanation:
Similar questions