How much heat energy is necessary to raise the temperature of 5 kg of water from 20℃ to 100℃ ? In kcal.
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Explanation:
Given:
Mass= 5kg
Temperature 1 = 20 °C, Temperature 2= 100°C
Chamge in temperature= 100-20=80°C
we know that,
Q = m ×C × change in temperature
where, C= specific heat capacity of water =4200J/(kg K)
Q = 5 × 4200 × 80
=1680000 Joule
=1680 KJ
Q =401.52 K cal
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