Question

How much heat energy is necessary to raise the temperature of 6 kg of water from 20 degree C to 100 degree C? (specific heat capacity of water =1 kcal/kg °C) *
pls don't spam​

Answer 1

Answer:

Explanation:

. Given: Mass (m) = 5 kg

Temp. difference (∆T) = 100 - 20 = 80°C

Specific heat capacity (c) = 1 kcal/kg°C

To find: Heat energy (Q) = ?

Formula: Q = mc∆T

Solution:Q = 5 × 1 × 80

= 400 kcal