How much heat energy is necessary to raise the temperature of 5 kg of water from 20 °C to 100°C ?
Answers
Answered by
0
Explanation:
Mass =5kg
T1 =20 ∘C,T 2=100 ∘C
ΔT=100−20=80 ∘C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
Answered by
1
Answer:
∆=100-20=80°C
specific heat capacity of water is 1°C
hence
heat energy required = 5×1×80
=400°joules
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