Question

How much heat energy is necessary to raise the temperature of 5 kg of water from 20c to 100c.​

Answer 1

Answer:

Quantity of heat required to raise 5 kg of water from 20 0C  to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of .C  is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.

Answer is  266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for  a Kilogram of water through just one degree  centigrade. So, we are to save  save energy .

Answer 2

Explanation:mass= m = 5 kg

specific heat of water = c = 1.0

change in temperature =∆t= 100°c -20°c= 80°c now

Heat = H = ?

H = m×c×∆t. H = 5×1.0×80

therefore answer is 400 joules

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