How much heat energy is necessary to raise the temprature of 5 kg of water from 20०c to 100०c *
2 points
40kcal
400Kcal
4000Kcal
200Kcal
Answers
Answered by
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Answer: Mass =5kg
T
1
=20
∘
C,T
2
=100
∘
C
ΔT=100−20=80
∘
C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
Explanation: mark me as the brainiest ans
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