Question

How much heat energy is required when 20 grams of ice at 0°c to convert watervapour
at 100°c???
if u tell the answer correctly i will send u 100marks
if u tell unnessary answer like i dont know i will report the answer ☺​

Answer 1

Answer: The answer is 3360000 joule. Sorry if I am sorry. I have tried my best to answer this question

Answer 2

2000 cal , 8360 J.

Explanation:

mass of water = 20 gm

Change in temperature = 100-0 = 100

Heat energy required = mass of water (gm)× Change in temperature (°C) cal.

$heat \: = mass \: \times change \: in \: temperaure$

= 20 × 100 = 2000 cal

$1joule \: = \: 4.18 \times 1cal$

=2000 × 4.18 = 8360 J