Question

how much heat energy is transformed when 2 grms of ice at -5°c turns into 100°c vapor??
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Answer 1

Answer:

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Answer 2

Explanation:

we use 2 equattion

1. q = m x c x dt
2. q = m x Lv

S(ice) = 0.5,

• First the ice melts to 5°---->0°

                        Q =  2 x 0.5 x 5 =5 cal

Lf = 80 cal

• Phase change 0° ice ---> 0° water

                         Q = 2 x 80 = 160 cal

S (water) = 1

• Water from 0° ------>100°

                         Q = 2 x 1 x 100 = 200 cal

Lv = 560

• Phase change 100°water ----> 100°vapour

                         Q = 2 x 540 = 1080 cal

Total heat = 1445 cal

                       Hope you understand

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