Question

How much heat energy must be removed from 1.2 g of lead (specific heat = 0.128 J/g ºC) to cool it from 37 ºC to 24 ºC?

Answer 1

Answer:

heat energy must be removed from 1.2 g of lead (specific heat = 0.128 J/g ºC) to cool it from 37 ºC to 24 ºC