Question

How much heat (in kJ) would be required to raise 250. g of liquid water from 25.0°C to 75.0°C?

Answer 1

Answer:

52.5 kJ

Explanation:

Specific heat of water = 4200 J/kgc

$\frac{250}{1000} \times 4200 \times (75 - 25) \\ 52500 \\ 52.500 \:$