Question

How much heat is absorbed by a 200 g granite piece as energy from the sun causes its temperature to change from 15 °C to 35 °C (specific heat capacity
of granite is 0.1 calg-1 •c-1?​

Answer 1

Answer:

How much heat is absorbed by a 200 g granite piece as energy from the sun causes its temperature to change from 15 °C to 35 °C (specific heat capacity

of granite is 0.1 calg-1 •c-1?

Ans:)Heat absorbed,

Heat absorbed,H=m.

Heat absorbed,H=m.c.

Heat absorbed,H=m.c.∂(θ)

θ)

θ) Where, m= mass,

θ) Where, m= mass,C= specific heat capacity. Assume

θ) Where, m= mass,C= specific heat capacity. Assume c=790J

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K for granite.

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K for granite.∂(θ)

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K for granite.∂(θ) is the change in temperature.

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K for granite.∂(θ) is the change in temperature.Hence,

θ) Where, m= mass,C= specific heat capacity. Assume c=790Jkg/K for granite.∂(θ) is the change in temperature.Hence, ∂(θ)=

θ)=29−

θ)=29−10=

θ)=29−10=19K

θ)=29−10=19K

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅19=

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅19=3002000J

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅19=3002000J=

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅19=3002000J=3.002

θ)=29−10=19K (Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)Then we have,H=2000⋅790⋅19=3002000J=3.002MJ

Answer 2

Answer:

हाउ आर यू कैन कंट्रोल डिस्ट्रीब्यूशन ऑफ प्लांट बाय ह्यूमन नेम