how much heat is absorbed when 1 kg of a liquid gets vapourized at its boiling point
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Nyc question............
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dont u know the answer????
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At its boiling point, the latent heat of vapourisation comes into the picture.
Its value is 540 cal/g
Heat absorbed by 1000 grams of liquid = mass x latent heat of vapourisation
= 1000 x 540 calories
= 540 kilocalories
= 2259.36 kilo joules
Its value is 540 cal/g
Heat absorbed by 1000 grams of liquid = mass x latent heat of vapourisation
= 1000 x 540 calories
= 540 kilocalories
= 2259.36 kilo joules
i considered the liquid as water.... else it cannot be solved
they must specify it in the question as........
latent heat of vapourisation is a characteristic of a liquid
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