Question

How much heat is added if .617g of water is increased in temperature by .241 degrees C?

Answer 1

Answer:

0.622J

Explanation:

In order to solve this problem, you need the formula:

q

=

m

C

s

Δ

T

Assuming water is in its liquid state, the specific heat capacity or

C

s

would be 4.18

J

g

⋅

d

e

g

r

e

e

s

C

e

l

s

i

u

s

Δ

T

in this case would be 0.241 degrees Celsius since this represents the change in temperature.

m

would be 0.617 grams.

Plug in all the values and you would get 0.622 joules!