how much heat is released in converting 5g of steam at 100°c to water at 30°c?Lsteam=540cal/g
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Amount of heat required = Change the temp Of Ice from -10 C to 0 C + Heat required to melt the Ice + Heat required to increase the temperature of water from 0 to 100 C + Heat required to convert water at 100 C to vapor at 100 C
=1×0.5[0−(−10)]+1×80+1×1×100+1×540=5+80+100+540=725cal
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