How much heat is required to change the temperature of 149.05 grams of heat ( specific heat capacity = 0.03 cal/g C presuperscript 0) from 10 to the power of 0 c space t o space 60 to the power of 0 C?
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Answer:
Correct option is
C
167.4
o
C
Let m be the mass of the bullet. The kinetic energy :
K.E=
2
1
mv
2
=
2
1
×m×(300)
2
=45000J
According to the law of conservation of energy, θ being the rise in
temperature
2
m×45000
=m×4.2×10
3
×0.32×θ
θ=
2×4.2×10
3
×0.032
45000
=167.41
∘
C
Explanation:
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