Question

How much heat is required to change the temperature of 149.05 grams of heat ( specific heat capacity = 0.03 cal/g C presuperscript 0) from 10 to the power of 0 c space t o space 60 to the power of 0 C?

Answer 1

Answer:

m be the mass of the bullet. The kinetic energy :

K.E=

2

1

mv

2

=

2

1

×m×(300)

2

=45000J

According to the law of conservation of energy, θ being the rise in

temperature

2

m×45000

=m×4.2×10

3

×0.32×θ

θ=

2×4.2×10

3

×0.032

45000

=167.41

∘

C