how much heat is required to convert: 1g of ice at ) 0 degree Celsius into water 0 degree celsius?
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Heat required to convert 1 g of ice at 0° C into water 0°C is 420 J.
Explanation:
Ice and water exist at 0°C. Here the first ice changes to water, but the temperature will be the same, i.e. it will become water at 0°C.
We know that, Heat = Mass of the ice x Latent heat of fusion of ice
= .001 × 3.35 × 10⁵ = 335J.
After heating the water, ∆T is change in temperature, H = mc∆T.
where m is mass in kg
c = specific heat
water = 4200J/kg
Ice = 2100 J/kg
So, H = .001 × 4200 × (100 – 0) = 420J
Therefore, Heat required to convert 1 g of ice at 0° C = 420 J.
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