How much heat is required to heat 250 g of water from 0℃ to 80℃? Remember to calculate ∆T (∆T = final T – initial T). The specific heat of water is 4.2 J/g℃.
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Answer:
Q = ms(T2-T1)
= 250×4.2(80)
=84000J
Hence 84000J heat is required.
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