Question

how much heat is required to increase the temperature of 0.5kg water from 10°C to 65°C​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Δ Q = 115500J

Explanation:

Mass of water = m = 0.5 kg

Initial temperature =  = 10°C = 10 + 273 = 283 K

Final temperature =  = 65°C = 65 + 273 = 338 K

Change in temperature = Δ T =  –  = 338 – 283 = 55 K

Heat = Δ Q = ?

Δ Q = mc Δ T

Δ Q = 0.5  2400 55

Δ Q = 115500J