Question

How much heat is required to melt 3Kg of ice completely in to water at the melting point of water. Latent heat of fusion of ice = 3.35 × 105 J kg–1 ​

Answer 1

Answer:

⇒ΔTwater=(273.15+50)−(273.15+6.7)

⇒ΔTwater=43.3K

Substitute 0.30kgfor the mass of water, 4186J.kg−1K−1

for the heat capacity of water and 43.3K for temperature change.

qwater=0.30kg×4186J.kg−1K−1×43.3K

qwater=54376.14J

Explanation:

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