Question

how much heat is required to raise the temperature of 0.15kg of water from 20° C to 35°C?​

Answer 1

Answer:

9450 J

Explanation:

Energy = mass × specific heat capacity × temp. change

Energy = 0.15 kg × 4200 J/(kg °C) × (35°C - 20°C)

Energy = 0.15 kg × 4200 J/(kg °C) × 15°C

Energy = 9450 J