how much heat is required to raise the temperature of 10 gram of water from 25 degree centigrade to 75 degree centigrade
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Q=m×c×∆T
=0.01×4.18×50
=0.59J/kg℃
the answer is 0.59J/kg℃
=0.01×4.18×50
=0.59J/kg℃
the answer is 0.59J/kg℃
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