How much heat is required to raise the temperature of 100 g of water from 5°C to 95°C ?
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Given, m= 100g, 0,= 5°C,0₂ = 95°C
We have, specific heat of water c =
1cal/g °C
Now, heat required to raise the temperature of water is given by, Q = mcA0 = mc(0₂-0₁)
or
Q=100x1x (95-5)=
9000cal = 9kcal
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