How much heat is required to raise the temperature of 10kg of water by 30 degrees C?
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We know that, to change the state of a matter, heat is required. Heat required to change a solid into liquid is given by ,
Q=mL ,
where L= latent heat of fusion ,
now given that , m=10 kg , and latent heat of fusion of ice is , L=336×10
3
J/kg ,
hence, heat required to convert the 10kg of ice at 0
o
C to water at 0
C ,
Q=(10×336×10
3
)=3360 kJ ,
now, heat required to convert the 10kg of water at 0
o
C to water at 50
o
C ,
by , Q
′
=m×c×Δt ,
given c=4200J/kg
o
C ,
hence Q
′
=10×4200×(50−0)=2100 kJ ,
therefore total heat required to convert 10kg of ice at 0
o
C to water at 50
o
C ,
Q
′′
=Q+Q
′
=3360+2100=5460 kJ
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