how much heat is required to raise the temperature of an aluminium kettle of mass 400gm through 90 degree c?
Answers
Explanation:
Explanation:
Q. How much heat is required to raise the temperature of an aluminum kettle of mass 400gm through 900C if the Sp. Heat capacity of aluminum is 899J/Kg0?
Ans. First, let’s fix the errors here.
This should read:
“How much heat is required to raise the temperature of an aluminum kettle of mass 400 g through 900 °C if the Sp. Heat capacity of aluminum is 899 J/kg·°C?”
or else:
“How much heat is required to raise the temperature of an aluminum kettle of mass 400 g through 90 °C if the Sp. Heat capacity of aluminum is 899 J/kg·°C?”
Note that the symbol for grams is ‘g’, not ‘gm’; the symbol for kilograms is ‘kg’, not ‘Kg’; the symbol for degrees Celsius is ‘°C’, not ‘C’; and that there is a required space after a coefficient, as in “400 g” instead of “400g”. (Accurate notation is important, especially in the sciences.)
I suspect that the latter reading is the correct one, since the melting point of aluminum is less than 900 °C.
Now: when you multiply a specific-heat capacity by a mass, the mass units cancel; similarly, when you multiply by a temperature change (such as 900 °C or 90 °C), the temperature units cancel. Doing both of these leaves only units of energy, which is what you seek here.
Perform the needed multiplications — remembering to convert g to kg — and you’ll have your answer.
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