Question

how much heat is requirwd to raise the temperature of 5 kg water from 20 degree to 100 degree celcius​

Answer 1

Answer:

Step-by-step explanation:

Quantity of heat required to raise 5 kg of water from 20 0C  to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.)For water, the value of .C  is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.

Answer is  266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heat

Answer 2

C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules. Thus 4180 Joules of energy of heats required for a Kilogram of water through just one degree centigrade.

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