Question

how much heat os required to raise ths temperature of 100gm of water from 5°c to 95°c​

Answer 1

$\bf{Given}\begin{cases}\sf{mass(m)=100gm}\\ \</p><p>\sf{T_{1}=5°C}\\ \ \sf{T_{2}=95°C}\end{cases}$

$\underline{\bf{To\:Find:}}$

•$\textsf{ Heat required to raise the temperature (Q)}$

$\underline{\bf{Solution:}}$

As we know

Q= mC∆T

and specific heat capacity of water is 4.186 joule/gram°C

putting the values we get,

→ 100× 4.186×(95-5)

→ 100× 4.186× 90

→ 37, 674 J

•°• Heat required to raise the temperature is 37,674 J