How much heat should be supplied to convert ice of mass 250 g at 0℃ into water at 20℃.
Please send the answer in picture if possible.
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Answered by
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Hey dear here is your answer!!!!!
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Firstly we need to convert the ice form of water into water form through latent heat of fusion for ice which is 384J/gram. So to convert 250g of ice into water we need 384 x 20 = 7680J.
Now, to raise the temperature of water up to 20°C we need to provide it some heat.
Specific heat capacity of water is 4.184J/g/°C.
To heat 250g water up to 20°C we need 250 x 20 x 4.184 = 20920J.
Total energy needed = 7680 + 20920 = 28600J.
Sorry for written explanation even when you asked for answer in pictures.
❣️⭐ Hope it helps u dear...⭐⭐❣️❣️
___________________________
Firstly we need to convert the ice form of water into water form through latent heat of fusion for ice which is 384J/gram. So to convert 250g of ice into water we need 384 x 20 = 7680J.
Now, to raise the temperature of water up to 20°C we need to provide it some heat.
Specific heat capacity of water is 4.184J/g/°C.
To heat 250g water up to 20°C we need 250 x 20 x 4.184 = 20920J.
Total energy needed = 7680 + 20920 = 28600J.
Sorry for written explanation even when you asked for answer in pictures.
❣️⭐ Hope it helps u dear...⭐⭐❣️❣️
jailbreakerios10:
Hey the answer should come in cal.
Answered by
1
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As we know about heating.
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Huy guys,
......................
Question is How much heat should be supplied to convert ice of mass 250 g at 0℃ into water at 20℃.
So,
Answer is
4676.8 J
.................................................
ALSO DON'T FORGOT TO MARK ME BRAINLIST.
As we know about heating.
................................................
Huy guys,
......................
Question is How much heat should be supplied to convert ice of mass 250 g at 0℃ into water at 20℃.
So,
Answer is
4676.8 J
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