Question

how much heat should be supplied to convert ice of mass 50g at 0 degree celcius into water st 40 degree celcius​

Answer 1

Answer:

2kcal

Explanation:

heat=mass×rise in temperature×specific heat capacity

specific heat capacity of water =1 cal/J°

rise in temperature =40-0=40°C

mass=50g

heat =50×1×40

heat=2000Cal

heat=2kcal

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Answer 2

Answer:

hey mate here is your answer ❤️

when ice is at 0° C temperature and we now rise the temperature , ice melts and forms water.

here in question, we have require to find the amount of heat required to convert 50gm of cake at 0°C to water at 0°C.

use, Heat = mlf

here, m is mass of ice and is latent of fusion.

basically latent heat of fusion of ice = 80cal/gm

so, Heat = 50gm × 80cal/gm

= 4000cal

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