how Much heat will be required to raise the temperature of 200 gm of pure water at 30 °C to 90°C. No spamming otherwise I will report her or him .Just write the correct ans and explain it how it has came . I hope I have made myself clear.
Answers
Answered by
1
Answer:
12000 calories
Explanation:
Change in temperature Formula:
Mass × Specific Heat Capacity × Change in Temperature
= 200 × 1 × 60
=12000 cals or 12kcal
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Answered by
3
Answer:
12000 calories
Explanation:
Change in temperature Formula:
Mass x Specific Heat Capacity * Change
in Temperature
= 200 × 1 × 60
=12000 cals or 12kcal
hope it helps you
please mark me as brainliest
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