Question

how Much heat will be required to raise the temperature of 200 gm of pure water at 30 °C to 90°C. No spamming otherwise I will report her or him .Just write the correct ans and explain it how it has came . I hope I have made myself clear.

Yes i guess​

Answer 1

Answer:

12000 calories

Explanation:

Change in temperature Formula:

Mass × Specific Heat Capacity × Change in Temperature

= 200 × 1 × 60

=12000 cals or 12kcal

Answer 2

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