How much heat would be absorbed by 2 litres of an ideal gas at 5 atm pressure if it expands isothermally into an evacuated flask of 5 litres
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From first law of thermodynamics
Heat absorbed = Work done on the system
= P∆V
= 5 atm × (5 L - 2 L)
= 15 L atm
= 15 L atm × 101.33 J / (L atm)
= 1519.95 Joule
∴ 1519.95 Joule of heat is absorbed
Heat absorbed = Work done on the system
= P∆V
= 5 atm × (5 L - 2 L)
= 15 L atm
= 15 L atm × 101.33 J / (L atm)
= 1519.95 Joule
∴ 1519.95 Joule of heat is absorbed
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