Question

how much high above the ground, a boy can throw the ball if he is able to throw the same ball up-to maximum horizontal distance of 50m? ​

Answer 1

Answer:25m

Explanation:

The horizontal range is maximum (R-max) when the angle of projection is 45 degree.

R-max = (u^2)/g

So, (u^2)/g = 50 m ...(i)

For vertical motion,

Maximum Height (H)

= (u^2)/2g

= (u^2)/g × (1/2) ...(just rearranged the above equation)

= 50 × (1/2)

= 25 m

Thus, the maximum height till which the boy can throw the ball is 25 m.