Question

How much horizontal acceleration should be provided to the wedge so that the mass of block m placed on the wedge falls freely??

Answer 1

$\textbf{Answer ==>}$

$\textbf{For free fall, normal reaction should be 0}$

$\textbf{N = 0}$

0 + masin$\theta{}$ = mgcos$\theta{}$

a = g / tan$\theta{}$

$\textbf{Hope it helps u}$✌

Answer 2

Hey mate......

here's your answer.......

Free fall condition needs...

Normal reaction equal to 0

N will be 0 ...

0 + mgsin(theta) = mgcos(theta)..

a = g/tan(theta)

Where = a = acceleration

g = gravitational force

mg = Mass × gravity....

Hope it helps....

Be brainly