Question

how much hydrogen chloride gas can be prepared by 10 g of hydrogen​

Answer 1

Answer:

365 g of hydrogen chloride gas can be prepared by 10 g of hydrogen​

Explanation:

The chemical equation for the formation of hydrogen chloride gas is

$H_{2}_{(g)} +Cl_{2} _{(g)}$   →    $2HCl_{(g)}$

Here one mole of hydrogen and one mole of chlorine gives two moles of hydrogen chloride.

The molecular mass of $H_{2}$ = 2 g/mol

The molecular mass of HCl = 1+35.5 = 36.5 g/mol

That is 2 g of hydrogen gives 2× 36.5 = 73 g of hydrogen chloride

∴ 10 g of hydrogen ⇒ 5 ×73 = 365 g of hydrogen chloride