Question

How much hydrogen is required to react conpletely with 0.6g of hydrogen to form ammonia NH3?

Answer 1

Answer:

10.80 g of

H

2

Explanation:

As per the equation, let us calculate the mole ratio.

N

2

+

3

H

2

→

2

N

H

3

As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio;

28.01 g of

l

N

2

needs

6.048 g of

l

H

2

1 g of

l

N

2

needs

6.048

28.01

g  of

l

H

2

50.0 g of

l

N

2

needs

6.048

×

50.0

28.01

l

g of

l

H

2

=

10.80 g of

l

H

2