How much hydrogen will be obtained from a mixture containing 8 g of LiH and 21g of CaH2
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Explanation:
CaH
2
+2H
2
O→Ca(OH)
2
+2H
2
↑
The molar mass of CaH
2
=40+2=42 g/mol.
The number of moles of CaH
2
=
42g/mol
42g
=1mol
1 mole of CaH
2
will liberate 2 moles of H
2
The molar mass of H
2
=2 g/mol
The mass of H
2
gas obtained =2g/mol×1mol=2g
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