Question

how much I get is required to prepare 200ml of decimolar solution
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Answer 1

Answer:

Explanation:

A decimolar solution is a solution having one- tenth the concentration of a molar solution. In other words, decimolar solution means 1/10 M.

37 ml of solute/100 ml of solution. Therefore add 8.3 ml of 37% HCL to 1 liter of D5W or NS to create a 0.1N HCL solution. 12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/ml. 0.1 M x 36.5 = 3.65 g/L = 3650 mg.