Math, asked by bhava006, 7 months ago

how much ice cream can be put into a cone with base radius 3.5 cm and height 12cm ?​

Answers

Answered by KARTAVYAJUNEJA
0

Step-by-step explanation:

Given that ,

Given that ,=> Radius of cone (r) = 3.5 cm

Given that ,=> Radius of cone (r) = 3.5 cm=> Height of cone (h) = 12 cm

Given that ,=> Radius of cone (r) = 3.5 cm=> Height of cone (h) = 12 cm•°• Amount of ice cream that can be filled = Volume of Cone

Given that ,=> Radius of cone (r) = 3.5 cm=> Height of cone (h) = 12 cm•°• Amount of ice cream that can be filled = Volume of Cone➡Volume of Cone = ⅓ πr²h

Given that ,=> Radius of cone (r) = 3.5 cm=> Height of cone (h) = 12 cm•°• Amount of ice cream that can be filled = Volume of Cone➡Volume of Cone = ⅓ πr²h=> 15400 cm³

Given that ,=> Radius of cone (r) = 3.5 cm=> Height of cone (h) = 12 cm•°• Amount of ice cream that can be filled = Volume of Cone➡Volume of Cone = ⅓ πr²h=> 15400 cm³➡Hence , the amount of ice cream that can be filled in the cone is 15400cm³

Answered by Anonymous
2

Given ,

Radius of cone (r) = 3.5 cm

Height of cone (h) = 12 cm

We know that , the volume of cone is given by

 \boxed{ \tt{Volume =  \frac{1}{3} \pi {(r)}^{2} h}}

Thus ,

 \tt  \implies Volume =  \frac{1}{3}  \times  \frac{22}{7}  \times  3.5  \times 3.5 \times 12

 \tt  \implies Volume =  \frac{22 \times 12.25 \times 12}{3 \times 7}

 \tt  \implies Volume = 22 \times 1.75 \times 4

 \tt  \implies Volume = 22 \times 7

 \tt  \implies Volume = 154 \:  \:  {cm}^{3}

Hence , the amount of ice cream is 154 c

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