How much iron (in kg) is obtained from 320 kg of iron(iii) oxide
Answers
Answered by
11
Answer:
Fe = 2xAr Fe / Mr Fe2O3 x 320 kg
Fe = (2x56) / 160 x 320 kg
Fe = 224 kg
Hope you understood
Answered by
5
Answer:
224kg.
Explanation:
Fe = 2xAr Fe / Mr Fe2O3 x 320 kg
Fe = (2x56) / 160 x 320 kg
Fe = 224 kg.
Hope it helps you.
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