Question

How much iron (in kg) is obtained from 320 kg of iron(iii) oxide

Answer 1

Answer:

Fe = 2xAr Fe / Mr Fe2O3  x 320 kg

Fe = (2x56) / 160   x  320 kg

Fe = 224 kg 

Hope you understood

Answer 2

Answer:

224kg.

Explanation:

Fe = 2xAr Fe / Mr Fe2O3 x 320 kg

Fe = (2x56) / 160 x 320 kg

Fe = 224 kg.

Hope it helps you.