How much iron is needed to make a rod of diameter 1.4 cm and length 30 cm?
Answers
Answered by
2
Step-by-step explanation:
Total length=30 cm
Diameter=1.4 cm
Radius=1/2× Diameter
=1/2×1.4
=0.7 cm
Total iron required= Volume of cylinder
=πr^2h
=22/7×0.7×0.7×30
=46.2 cm^3
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Answered by
50
Given :
- Length of rod, l = 30 cm
- Diameter of rod, d = 1.4cm
- Radius of rod, r = d/2 = 1.4/2 = 0.7cm
To Find :
- Iron needed to make a rod.
Solution :
We have, r = 0.7 , l = 30
Volume of rod = πr²l
= 22/7 × 0.7 × 0.7 × 30
= 22 × 0.1 × 0.7 × 30
= 22 × 0.7 × 3
= 66 × 0.7
= 46.2cm³
Thus, 46.2cm³ iron is needed to make a rod of diameter 1.4 cm and length 30 cm.
→ Additional information :
- Volume of a cuboid = lbh
- Voume of a cube = l³
- Volume of a cylinder = πr²h
- Volume of a cone =1/3 πr²h
- Volume of a sphere = 4/3 πr³
- Volume of a hemisphere = 2/3 πr³
- Volume of a hollow cylinder = π( R²-r² )h
- Volume of a frustrum of cone = 1/3 πh(R²+r²+Rr)
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