Question

How much iron sheet is required to prepare
a box dimension 25cm x 18cm x 12cm.if it is the top.
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Answer 1

Correct Question:

How much iron sheet is required to prepare a box with the dimensions 25cm by 18cm by 12cm, if it is open at the top?

Final Answer:

The iron sheet that is required to prepare a box with the dimensions 25cm by 18cm by 12cm, if it is open at the top, is of area $1482\;cm^2$.

Given:

The box is with dimensions 25cm by 18cm by 12 cm, and it is open at the top.

To Find:

The iron sheet that is required to prepare a box with the dimensions 25cm x 18cm x 12cm, if it is open at the top.

Explanation:

The following points are important to arrive at the solution to the present problem.

• A box open at the top has one rectangular bottom side, and four rectangular lateral sides with a hollowness inside the box, to store the essentials within.

• The iron sheet needed for the box open at the top is calculated considering all the sides including the rectangular bottom side, and the four rectangular lateral sides.

Step 1 of 3

As per the statement in the given problem, note the following.

• The box open at the top measuring 25cm by 18cm by 12 cm is supposed to have an overall length of 25cm, an overall breadth of 18cm, and an overall height of 12cm.

• The rectangular bottom side of the box covers an area of length of 25 cm and a breadth of 18 cm.

• Two of the four rectangular lateral sides of the box cover an area of length of 25 cm and a breadth of 12 cm.

• The other two of the four rectangular lateral sides of the box cover an area of length of 18 cm and a breadth of 12 cm.

Step 2 of 3

In accordance with the above calculations, the following is derived.

• The area of the rectangular bottom side of the box with a length of 25 cm and a breadth of 18 cm. is

$=25\times 18\\=450\;cm^2$

• The area of the rectangular lateral side of the box with a length of 25 cm and a breadth of 12 cm is

$25\times 12\\=300\;cm^2$

• The area of the rectangular lateral sides of the box with a length of 18 cm and a breadth of 12 cm is

$18\times 12\\=216\;cm^2$

Step 3 of 3

Now, the total area covered by the box with the dimensions 25cm by 18cm by 12cm, which is open at the top, is

$=450+2\times 300+2\times 216\\=450+600+432\\=1482\;cm^2$

Therefore, the required iron sheet that is required to prepare a box with the dimensions 25cm by 18cm by 12cm, if it is open at the top, is of area $1482\;cm^2$.

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Answer 2

Answer:

Since, to make box approx 101 box required.

Step-by-step explanation:

Step 1: Material that is stirred Iron or steel sheets are a slender, ridged sheet-based roofing material that is lightweight. The strength and inflexibility of the lightweight material are essentially expanded by foldings, like waves. The most affordable decision is metal material sheets, which are additionally the most persevering. While polycarbonate sheets are clear and appropriate for outside use, plastic material sheets are lightweight and clear. Accordingly, the ideal sheet will depend on the particular requirements and spending limit.

Step 2: The bodywork of vehicles and trucks (trucks), enormous machines, plane fuselages and wings, tinplate for metal jars, material for structures (design), and numerous different things are made of sheet metal.

Step 3: We know that complete surface area of cuboid =2(lb+bh+hl)

=2(25×18+18×12+12×25)

=2(450+216+200)

= 1732 cm^2

Thus, volume of iron sheets are 25×19×12 = 5700

then, at that point, sheet expected for set up a container = 5700÷56

since, to make box approx 101 box required.

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