how much is 0 greater than -a2-ab+7b2
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a2-ab+7b2
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-a2+ab-7b2 (Ans)
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Answer:
a²+ab-7b² times 0 is greater than (-a²-ab+7b²) .
Step-by-step explanation:
To know how much greater an equation is from 0 we need to subtract the equation by 0.
as our equation is -a²-ab+7b².
let's subtract it by 0.
=0-(-a²-ab+7b²)
=a²+ab-7b².
hence ,
(-a²-ab+7b²) times 0 is greater than (a²+ab-7b²) .
(#SPJ3)
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