How much is 0 greater than -a2-ab+7b2 ? please solve this question
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hey mate your answer plz mark as brainlist
- Solution:
- Let k be one of the root of the given equation.
- According to the problem,
- 1/k will be the other root of the given equation.
- We know that, product of the roots of the equation = c/a.
- Therefore, k × 1/k = c/a.
- or, 1 = c/a.
- or, a = c [multiplying a on both sides].
- The roots of the equation ax2 + bx + c = 0 will be reciprocal if a = c.
- Therefore, a = c or c = a.
- Answer: (c)
- 3. If 8 ∙ 2x = 5(y+8), then when y = -8, x =
- (a) -4, (b) -3, (c) 0, (d) 4, (e) 8
- Solution:
- 8 ∙ 2x = 5(y+8).
- or, 8 ∙ 2x = 5(-8+8).
- or, 2x = 50.
- or, 2x = 1 [anything to the power 0 is 1 then, 50 = 1].
- Taking log on both sides,
- log 2x = log 1.
- or, x log 2 = 0 [since log 1 = 0].
- or, x = 0/log 2 [dividing log 2 on both sides].
- Therefore, x = 0.
mahisingh89:
hi
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Answer:
very much greater is zero than above
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