Math, asked by Anonymous, 9 months ago

How much is 1+2+3+4+5 ... +2020?

Answers

Answered by irfan1728

1

by using formula for the sum of nth natural number:

n(n+1)/2

=2020(2020+1)/2

=1010×2021

=2041210

please mark as brainliest✌❤

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